Optimal. Leaf size=393 \[ -\frac{c^{3/4} \sqrt{x} \left (\sqrt{a}+\sqrt{c} x\right ) \sqrt{\frac{a+c x^2}{\left (\sqrt{a}+\sqrt{c} x\right )^2}} \left (25 \sqrt{a} B+63 A \sqrt{c}\right ) \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{a}}\right ),\frac{1}{2}\right )}{30 a^{11/4} e^3 \sqrt{e x} \sqrt{a+c x^2}}-\frac{21 A c^{3/2} x \sqrt{a+c x^2}}{5 a^3 e^3 \sqrt{e x} \left (\sqrt{a}+\sqrt{c} x\right )}+\frac{21 A c^{5/4} \sqrt{x} \left (\sqrt{a}+\sqrt{c} x\right ) \sqrt{\frac{a+c x^2}{\left (\sqrt{a}+\sqrt{c} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{5 a^{11/4} e^3 \sqrt{e x} \sqrt{a+c x^2}}+\frac{21 A c \sqrt{a+c x^2}}{5 a^3 e^3 \sqrt{e x}}-\frac{7 A \sqrt{a+c x^2}}{5 a^2 e (e x)^{5/2}}-\frac{5 B \sqrt{a+c x^2}}{3 a^2 e^2 (e x)^{3/2}}+\frac{A+B x}{a e (e x)^{5/2} \sqrt{a+c x^2}} \]
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Rubi [A] time = 0.503864, antiderivative size = 393, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 7, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.292, Rules used = {823, 835, 842, 840, 1198, 220, 1196} \[ -\frac{c^{3/4} \sqrt{x} \left (\sqrt{a}+\sqrt{c} x\right ) \sqrt{\frac{a+c x^2}{\left (\sqrt{a}+\sqrt{c} x\right )^2}} \left (25 \sqrt{a} B+63 A \sqrt{c}\right ) F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{30 a^{11/4} e^3 \sqrt{e x} \sqrt{a+c x^2}}-\frac{21 A c^{3/2} x \sqrt{a+c x^2}}{5 a^3 e^3 \sqrt{e x} \left (\sqrt{a}+\sqrt{c} x\right )}+\frac{21 A c^{5/4} \sqrt{x} \left (\sqrt{a}+\sqrt{c} x\right ) \sqrt{\frac{a+c x^2}{\left (\sqrt{a}+\sqrt{c} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{5 a^{11/4} e^3 \sqrt{e x} \sqrt{a+c x^2}}+\frac{21 A c \sqrt{a+c x^2}}{5 a^3 e^3 \sqrt{e x}}-\frac{7 A \sqrt{a+c x^2}}{5 a^2 e (e x)^{5/2}}-\frac{5 B \sqrt{a+c x^2}}{3 a^2 e^2 (e x)^{3/2}}+\frac{A+B x}{a e (e x)^{5/2} \sqrt{a+c x^2}} \]
Antiderivative was successfully verified.
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Rule 823
Rule 835
Rule 842
Rule 840
Rule 1198
Rule 220
Rule 1196
Rubi steps
\begin{align*} \int \frac{A+B x}{(e x)^{7/2} \left (a+c x^2\right )^{3/2}} \, dx &=\frac{A+B x}{a e (e x)^{5/2} \sqrt{a+c x^2}}-\frac{\int \frac{-\frac{7}{2} a A c e^2-\frac{5}{2} a B c e^2 x}{(e x)^{7/2} \sqrt{a+c x^2}} \, dx}{a^2 c e^2}\\ &=\frac{A+B x}{a e (e x)^{5/2} \sqrt{a+c x^2}}-\frac{7 A \sqrt{a+c x^2}}{5 a^2 e (e x)^{5/2}}+\frac{2 \int \frac{\frac{25}{4} a^2 B c e^3-\frac{21}{4} a A c^2 e^3 x}{(e x)^{5/2} \sqrt{a+c x^2}} \, dx}{5 a^3 c e^4}\\ &=\frac{A+B x}{a e (e x)^{5/2} \sqrt{a+c x^2}}-\frac{7 A \sqrt{a+c x^2}}{5 a^2 e (e x)^{5/2}}-\frac{5 B \sqrt{a+c x^2}}{3 a^2 e^2 (e x)^{3/2}}-\frac{4 \int \frac{\frac{63}{8} a^2 A c^2 e^4+\frac{25}{8} a^2 B c^2 e^4 x}{(e x)^{3/2} \sqrt{a+c x^2}} \, dx}{15 a^4 c e^6}\\ &=\frac{A+B x}{a e (e x)^{5/2} \sqrt{a+c x^2}}-\frac{7 A \sqrt{a+c x^2}}{5 a^2 e (e x)^{5/2}}-\frac{5 B \sqrt{a+c x^2}}{3 a^2 e^2 (e x)^{3/2}}+\frac{21 A c \sqrt{a+c x^2}}{5 a^3 e^3 \sqrt{e x}}+\frac{8 \int \frac{-\frac{25}{16} a^3 B c^2 e^5-\frac{63}{16} a^2 A c^3 e^5 x}{\sqrt{e x} \sqrt{a+c x^2}} \, dx}{15 a^5 c e^8}\\ &=\frac{A+B x}{a e (e x)^{5/2} \sqrt{a+c x^2}}-\frac{7 A \sqrt{a+c x^2}}{5 a^2 e (e x)^{5/2}}-\frac{5 B \sqrt{a+c x^2}}{3 a^2 e^2 (e x)^{3/2}}+\frac{21 A c \sqrt{a+c x^2}}{5 a^3 e^3 \sqrt{e x}}+\frac{\left (8 \sqrt{x}\right ) \int \frac{-\frac{25}{16} a^3 B c^2 e^5-\frac{63}{16} a^2 A c^3 e^5 x}{\sqrt{x} \sqrt{a+c x^2}} \, dx}{15 a^5 c e^8 \sqrt{e x}}\\ &=\frac{A+B x}{a e (e x)^{5/2} \sqrt{a+c x^2}}-\frac{7 A \sqrt{a+c x^2}}{5 a^2 e (e x)^{5/2}}-\frac{5 B \sqrt{a+c x^2}}{3 a^2 e^2 (e x)^{3/2}}+\frac{21 A c \sqrt{a+c x^2}}{5 a^3 e^3 \sqrt{e x}}+\frac{\left (16 \sqrt{x}\right ) \operatorname{Subst}\left (\int \frac{-\frac{25}{16} a^3 B c^2 e^5-\frac{63}{16} a^2 A c^3 e^5 x^2}{\sqrt{a+c x^4}} \, dx,x,\sqrt{x}\right )}{15 a^5 c e^8 \sqrt{e x}}\\ &=\frac{A+B x}{a e (e x)^{5/2} \sqrt{a+c x^2}}-\frac{7 A \sqrt{a+c x^2}}{5 a^2 e (e x)^{5/2}}-\frac{5 B \sqrt{a+c x^2}}{3 a^2 e^2 (e x)^{3/2}}+\frac{21 A c \sqrt{a+c x^2}}{5 a^3 e^3 \sqrt{e x}}-\frac{\left (\left (25 \sqrt{a} B+63 A \sqrt{c}\right ) c \sqrt{x}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{a+c x^4}} \, dx,x,\sqrt{x}\right )}{15 a^{5/2} e^3 \sqrt{e x}}+\frac{\left (21 A c^{3/2} \sqrt{x}\right ) \operatorname{Subst}\left (\int \frac{1-\frac{\sqrt{c} x^2}{\sqrt{a}}}{\sqrt{a+c x^4}} \, dx,x,\sqrt{x}\right )}{5 a^{5/2} e^3 \sqrt{e x}}\\ &=\frac{A+B x}{a e (e x)^{5/2} \sqrt{a+c x^2}}-\frac{7 A \sqrt{a+c x^2}}{5 a^2 e (e x)^{5/2}}-\frac{5 B \sqrt{a+c x^2}}{3 a^2 e^2 (e x)^{3/2}}+\frac{21 A c \sqrt{a+c x^2}}{5 a^3 e^3 \sqrt{e x}}-\frac{21 A c^{3/2} x \sqrt{a+c x^2}}{5 a^3 e^3 \sqrt{e x} \left (\sqrt{a}+\sqrt{c} x\right )}+\frac{21 A c^{5/4} \sqrt{x} \left (\sqrt{a}+\sqrt{c} x\right ) \sqrt{\frac{a+c x^2}{\left (\sqrt{a}+\sqrt{c} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{5 a^{11/4} e^3 \sqrt{e x} \sqrt{a+c x^2}}-\frac{\left (25 \sqrt{a} B+63 A \sqrt{c}\right ) c^{3/4} \sqrt{x} \left (\sqrt{a}+\sqrt{c} x\right ) \sqrt{\frac{a+c x^2}{\left (\sqrt{a}+\sqrt{c} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{30 a^{11/4} e^3 \sqrt{e x} \sqrt{a+c x^2}}\\ \end{align*}
Mathematica [C] time = 0.0630389, size = 107, normalized size = 0.27 \[ \frac{x \left (-21 A \sqrt{\frac{c x^2}{a}+1} \, _2F_1\left (-\frac{5}{4},\frac{1}{2};-\frac{1}{4};-\frac{c x^2}{a}\right )-25 B x \sqrt{\frac{c x^2}{a}+1} \, _2F_1\left (-\frac{3}{4},\frac{1}{2};\frac{1}{4};-\frac{c x^2}{a}\right )+15 (A+B x)\right )}{15 a (e x)^{7/2} \sqrt{a+c x^2}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.022, size = 331, normalized size = 0.8 \begin{align*}{\frac{1}{30\,{x}^{2}{e}^{3}{a}^{3}} \left ( 63\,A\sqrt{{\frac{cx+\sqrt{-ac}}{\sqrt{-ac}}}}\sqrt{2}\sqrt{{\frac{-cx+\sqrt{-ac}}{\sqrt{-ac}}}}\sqrt{-{\frac{cx}{\sqrt{-ac}}}}{\it EllipticF} \left ( \sqrt{{\frac{cx+\sqrt{-ac}}{\sqrt{-ac}}}},1/2\,\sqrt{2} \right ){x}^{2}ac-126\,A\sqrt{{\frac{cx+\sqrt{-ac}}{\sqrt{-ac}}}}\sqrt{2}\sqrt{{\frac{-cx+\sqrt{-ac}}{\sqrt{-ac}}}}\sqrt{-{\frac{cx}{\sqrt{-ac}}}}{\it EllipticE} \left ( \sqrt{{\frac{cx+\sqrt{-ac}}{\sqrt{-ac}}}},1/2\,\sqrt{2} \right ){x}^{2}ac-25\,B\sqrt{-ac}\sqrt{{\frac{cx+\sqrt{-ac}}{\sqrt{-ac}}}}\sqrt{2}\sqrt{{\frac{-cx+\sqrt{-ac}}{\sqrt{-ac}}}}\sqrt{-{\frac{cx}{\sqrt{-ac}}}}{\it EllipticF} \left ( \sqrt{{\frac{cx+\sqrt{-ac}}{\sqrt{-ac}}}},1/2\,\sqrt{2} \right ){x}^{2}a+126\,A{c}^{2}{x}^{4}-50\,aBc{x}^{3}+84\,aAc{x}^{2}-20\,{a}^{2}Bx-12\,A{a}^{2} \right ){\frac{1}{\sqrt{c{x}^{2}+a}}}{\frac{1}{\sqrt{ex}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{B x + A}{{\left (c x^{2} + a\right )}^{\frac{3}{2}} \left (e x\right )^{\frac{7}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{c x^{2} + a}{\left (B x + A\right )} \sqrt{e x}}{c^{2} e^{4} x^{8} + 2 \, a c e^{4} x^{6} + a^{2} e^{4} x^{4}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{B x + A}{{\left (c x^{2} + a\right )}^{\frac{3}{2}} \left (e x\right )^{\frac{7}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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